// n = 5
// k = 3
// 1, 2, 3
// 1, 2, 4
// 1, 2, 5
// 1, 3, 4
// 1, 3, 5
// 1, 4, 5
// 2, 3, 4
// 2, 3, 5
// 2, 4, 5
// 3, 4, 5
using System;
using System.Collections.Generic;
public static class GenerateCombinationsIteratively
{
    static void Main()
    {
        Console.Write("n = ");
        var n = int.Parse(Console.ReadLine());
        Console.Write("k = ");
        var k = int.Parse(Console.ReadLine());
        foreach (var combo in Combinations(k, n))
        {
            Console.WriteLine(string.Join(", ", combo));
        }
    }
    private static IEnumerable<int[]> Combinations(int k, int n)
    {
        var result = new int[k];
        var stack = new Stack<int>();
        stack.Push(1);
        while (stack.Count > 0)
        {
            var index = stack.Count - 1;
            var value = stack.Pop();
            while (value <= n)
            {
                result[index++] = value++;
                stack.Push(value);
                if (index == k)
                {
                    yield return result;
                    break;
                }
            }
        }
    }
}
	Tag: no repetition
How to generate Permutations without repetition iteratively in C#
// 1, 2, 3
// 2, 1, 3
// 3, 1, 2
// 1, 3, 2
// 2, 3, 1
// 3, 2, 1
// Total permutations: 6
using System;
using System.Linq;
public static class GeneratePermutationsIteratively
{
    public static void Main()
    {
        var num = int.Parse(Console.ReadLine());
        var numberOfPerm = 1;
        var elements = Enumerable.Range(1, num).ToArray();
        var workArr = Enumerable.Range(0, elements.Length + 1).ToArray();
        PrintPerm(elements);
        var index = 1;
        while (index < elements.Length)
        {
            workArr[index]--;
            var j = 0;
            if (index % 2 == 1)
            {
                j = workArr[index];
            }
            SwapInts(ref elements[j], ref elements[index]);
            index = 1;
            while (workArr[index] == 0)
            {
                workArr[index] = index;
                index++;
            }
            numberOfPerm++;
            PrintPerm(elements);
        }
        Console.WriteLine($"Total permutations: {numberOfPerm}");
    }
    private static void PrintPerm(int[] elements)
    {
        Console.WriteLine(string.Join(", ", elements));
    }
    private static void SwapInts(ref int a, ref int b)
    {
        a ^= b;
        b ^= a;
        a ^= b;
    }
}
	How to generate Combinations without repetition recursively in C#
// 1: [0, 1]
// 2: [0, 2]
// 3: [0, 3]
// 4: [1, 2]
// 5: [1, 3]
// 6: [2, 3]
using System;
public static class CombinationsNoRep
{
    private static int numberofCombos;
    private static int n;
    private static int k;
    private static int[] storageArr;
    public static void Main()
    {
        n = 4;
        k = 2;
        storageArr = new int[k];
        GenCombinationsNoRep();
    }
    private static void GenCombinationsNoRep(int index = 0, int element = 0)
    {
        if (index >= storageArr.Length)
        {
            PrintCombo();
            return;
        }
        for (int i = element; i < n; i++)
        {
            storageArr[index] = i;
            GenCombinationsNoRep(index + 1, i + 1);
        }
    }
    private static void PrintCombo()
    {
            Console.WriteLine(
                "{0,3}: [{1}]", 
                ++numberofCombos, 
                string.Join(", ", storageArr));
    }
}
	How to generate Variations without repetition recursively in C#
using System;
using System.Linq;
class VariationsWithoutRepetition
{
    const int k = 2;
    const int n = 4;
    static int[] arr = new int[k];
    static int[] free = Enumerable.Range(1, 4).ToArray();
    static void Main()
    {
        GenerateVariationsNoRepetitions(0);
    }
    static void GenerateVariationsNoRepetitions(int index)
    {
        if (index >= k)
        {
            PrintVariations();
        }
        else
        {
            for (int i = index; i < n; i++)
            {
                arr[index] = free[i];
                Swap(ref free[i], ref free[index]);
                GenerateVariationsNoRepetitions(index + 1);
                Swap(ref free[i], ref free[index]);
            }
        }
    }
    private static void Swap<T>(ref T v1, ref T v2)
    {
        T old = v1;
        v1 = v2;
        v2 = old;
    }
    static void PrintVariations()
    {
        Console.WriteLine("(" + string.Join(", ", arr) + ")");
    }
}
// result:
// (1, 2)
// (1, 3)
// (1, 4)
// (2, 1)
// (2, 3)
// (2, 4)
// (3, 2)
// (3, 1)
// (3, 4)
// (4, 2)
// (4, 3)
// (4, 1)
	How to generate Permutations without repetition recursively in C#
using System;
class GroupPermutations
{
    static void Main(string[] args)
    {
        string[] array = { "apple", "peach", "orange" };
        Perm(array, 0);
    }
    static void Perm<T>(T[] arr, int k)
    {
        if (k >= arr.Length)
            Print(arr);
        else
        {
            Perm(arr, k + 1);
            for (int i = k + 1; i < arr.Length; i++)
            {
                Swap(ref arr[k], ref arr[i]);
                Perm(arr, k + 1);
                Swap(ref arr[k], ref arr[i]);
            }
        }
    }
    private static void Swap<T>(ref T item1, ref T item2)
    {
        T temp = item1;
        item1 = item2;
        item2 = temp;
    }
    private static void Print<T>(T[] arr)
    {
        Console.WriteLine("{" + string.Join(", ", arr) + "}");
    }
}
//Result:
//{apple, peach, orange}
//{apple, orange, peach}
//{peach, apple, orange}
//{peach, orange, apple}
//{orange, peach, apple}
//{orange, apple, peach}